20x^2-8x=-10

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Solution for 20x^2-8x=-10 equation: 



20x^2-8x=-10

We move all terms to the left:

20x^2-8x-(-10)=0

We add all the numbers together, and all the variables

20x^2-8x+10=0

a = 20; b = -8; c = +10;
Δ = b2-4ac
Δ = -82-4·20·10
Δ = -736
Delta is less than zero, so there is no solution for the equation

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